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ab短路,求RN
RN = ( 4//2 ) + ( 4//8 ) = 4 歐姆
IN (流過ab的電流) = [ 18*4/(2+4) ] - [ 18*4/(8+4) ] = 6A
把2歐姆復原,並聯RN
I = 6*4/(2+4) = 4A
17 如圖所示,試求流過 a-b 點間 2Ω 電阻之電流為何? (A..-阿摩線上測驗