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統計： A(21), B(24), C(18), D(62), E(0) #296470

詳解 (共 1 筆)

#924381
tanθ + cotθ = sinθ/cosθ + cosθ/sinθ = [ (sinθ)^2+(cosθ)^2 ]/sinθcosθ = 1/sinθcosθ

又(sinθ+cosθ)^2 = 1+2sinθcosθ = 1/2
所以sinθcosθ = -1/4 代入
得 tanθ + cotθ = -4
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