Tm = Pm/W = Pg/Ws
Pg=100/0.025=4000
Ws=4*3.14*60/4=188.4
Tm=4000/188.4=21.2
轉矩:
Tm = Pm/ omegas
Pm = 100/0.025 = 4000 W
omegas = 120 f/p = 1800 rpm = 2 pi *1800 / 60 rad/s = 188.5 rad/s
帶回
Tm = 4000 / 188.5 = 21.221 N.m
故選 A
20.某三相、四極、60 Hz 感應電動機,已知滿載時轉差率為 0.025、轉子..-阿摩線上測驗