感謝樓上的回答!
2i = ( ix - i ) * 4 + 4ix
=> 3i - 4ix = 0 ----(1)
( ix - i ) * 4 = 0.5S * i - 5 ----- (2)
(1) 整理完 代入 (2) 再整理
=> ix = [ 7.5 / (S+2) ]
30. 有一電路如右圖,i(0) = 10 A。求t>0時,ix (t) ..-阿摩線上測驗