pOH = pKb + log[鹼]/[★]
=8.75+☆☆☆(0...
[OH-]=Kbxlog[鹼]/[鹽]
pOH = pKb - log[鹼]/[鹽]
=8.75-(log3-log5)
pH=5.03才對吧
49.對於吡啶(C5H5N),pKb = 8.75。0.300 MC5H5N(a..-阿摩線上測驗