9.某勞工每日作業時間8小時暴露於穩定性噪音,戴用劑量計測定2小時,其劑量爲25..-阿摩線上測驗
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2F Grace Yuan 國二下 (2021/03/28)
LTWA=16.61 x log(D) +90;(LTWA)t=16.61 x log(100D/12.5t) +90 測定t小時,t = 2;測定劑量D = 25%,100D = 25 (LTWA)t=16.61 x log(100D/12.5t) +90 = 16.61 x log(25/25) +90 = 16.61xlog1 +90 = 90 |