101年 - [無官方正解]101 國立嘉義大學_碩士班招生考試試題_生物農業科技學系：生物化學#146384

科目：研究所、轉學考(插大)◆生物化學 | 年份：101年 | 選擇題數：15 | 申論題數：5

試卷資訊

所屬科目：研究所、轉學考(插大)◆生物化學

選擇題 (15)

1. Substrate for glycogen phosphorylase (A) Glucose (B) Fructose (C) Sucrose (D) Pentose (E) Glycogen
2. Product of glycogen phosphorylase (A) Glucose 6-phosphate (B) Fructose 6-phosphate (C) Glucose 1-phosphate (D) Glyceraldehyde-3-phosphate (E) Fructose 1, 6-bisphosphate
3. Substrate for glycogen synthase (A) Glucose 6-phosphate (B) Glucose 1-phosphate (C) Fructose 6-phosphate (D) UDP-Glucose (E) Fructose 1, 6-bisphosphate
4. Product of glycogen synthase (A) Glucose (B) Fructose (C) Sucrose (D) Glycogen (E) Pentose
5. Which amino acid has hydrophobic side chain (A) Asparagine (B) Isoleucine (C) Lysine (D) Threonine (E) Proline
6. Product of fermentation in muscle cells (A) Glucose (B) Lactate (C) Glycerol (D) Fructose (E) Ribose
7. Compound that connects the urea cycle to the citrate cycle (is involved in both pathways) (A) Oxaloacetate (OAA) (B) Pyruvate (C) Acetyl-CoA (D) UDP-Glucose (E) Fructose 6-phosphate
8. The amino acid that contains a -S-CH3 group is (A) Methionine (B) Serine (C) Leucine (D) Histidine (E) Cysteine
9. What is the pH of a 1 mM solution of KOH? (A) 3 (B) 5 (C) 7 (D) 9 (E) 11
10. 1000 bps DNA coding sequences can make protein roughly (A) 23 (B) 27 (C) 33 (D) 37 (E) 43 kilodalton
1. Lipid components of membranes do not readily move from one side ofa bilayer to the other.(A)O(B)X
2. In the Citrate-Pyruvate Cycle, the step that generates NADPH is theconversion of pyruvate to acetyl CoA.(A)O(B)X
3. The precursor used to generate serine, glycine, and cysteine isoxaloacetate.(A)O(B)X
4. O2 is the ultimate acceptor of the electrons removed byoxidative decarboxylation in the TCA cycle.(A)O(B)X
5. Photosynthesis 的 light reactions 中，electrons 最後會傳到 water。(A)O(B)X

申論題 (5)

III. 問答題 (10 分)某一 enzyme 在其第 110 號 amino acid 為 glutamine，它位於此 enzymeprotein 的表面。 同時我們也發現了此 enzyme 在第 110 號 amino acid 有下列五種突變種，分別為a. glutamine → alanineb. glutamine → argininec. glutamine → asparagined. glutamine → glutamatee. glutamine → phenylalanine.請問
(1)那一種突變序列會使 enzyme 在跑 native gel electrophoresis 時，跑最快到陽極 ” ‐ “ 價處？為什麼？
(2)那一種突變序列會使 enzyme 與正常型 enzyme 功能相似？為什麼？
(3)那一種突變序列會有可能讓 110 號 amino acid 移入 protein 的內面？為什麼？
IV. 請分別說明細胞內脂肪代謝的分解。(25 分)
V. 細胞如何將過多的澱粉轉化成脂肪？ (25 分)