(二)為了去除臭味,經長時間曝氣後(空氣中 CO2 之壓力為 10-3.5 atm),失去所有氮及
硫,鹼度成為多少?(10 分) H2O = H+
+ OH- pK = 14.0
H2CO3 = HCO3
-
+ H+ pK1 = 6.3
HCO3
-
= CO3
2-
+ H+ pK2 = 10.3
NH4
+
= NH3 + H+ pK = 9.4
H2S = HS-
+ H+ pK1 = 7.0
HS-
= S2-
+ H+ pK2 = 13.9
( H=1, O=16, C=12, N=14, S=32)