(8)Given average kinetic energy, (K) = (kT), of a molecule in air at room temperature (20°C = 293K), please determine the root-mean-square speed of an O2 molecule with this energy. (k = 1.38×10⁻²³ J/K, 1u = 1.66×10⁻²⁷ kg)
(A)511 m/s
(B)671 m/s
(C)478 m/s
(D)823 m/s
(E)379 m/s
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(kT), of a molecule in air at room temperature (20°C = 293K), please determine the root-mean-square speed of an O2 molecule with this energy. (k = 1.38×10⁻²³ J/K, 1u = 1.66×10⁻²⁷ kg)
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