HCl 含有 20*3.65%=0.730g=0.02mole
HCl濃度=0.02(mole)/1(L)=0.02M=H+濃度
pH=2-log2=1.6990
HCl莫耳數 = (20ml x 3.65% (v/v) x 1.2g/ml)/ 36.5 = 0.024 mole
HCl濃度 = 0.024 mole/1L
pH = -log(24/1000) = -(log24-3) = -( 0.301 x 3 +0.4771 - 3) = 1.6199
1 取20 mL 比重為1.20 的3.65% HCl 水溶液,加水稀釋至100..-阿摩線上測驗