1. 某船依航向158°，航行48浬，之後轉向253°，航行72浬，最後轉向325°，航行36浬。請以聯向航法(Traverse Sailing)計算該船之實際航向(CMG)為何？
(A) 206.8°
(B) 243.2°
(C) 296.8°
(D) 333.2°

答案：登入後查看
統計： A(61), B(447), C(108), D(27), E(0) #2929084

詳解 (共 4 筆)

#5495996
先求出緯度差DL及橫距PCn=158 D...
(共 342 字，隱藏中）
前往觀看
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#6042169
65da890677427.jpg
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#6179650
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#6032044

Cn = 158 D = 48'，C = S22E

DL = cos22*48' = 44.5'S，P = sin22*48' = 18.0'E

Cn = 253 D = 72'，C = S73W

DL = cos73*72' = 21.1'S，P = sin73*72' = 68.9'W

Cn = 325 D = 36'，C = N35W

DL = cos35*36' = 29.5'N，P = sin35*36' = 20.6'W

DL = 44.5+21.1-29.5 = 36.1S

P = 18-68.9-20.6 = 71.5W

tanC = (71.5 / 36.1) = S63.2W -> 180+63.2 = 243.2

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私人筆記 (共 1 筆)

私人筆記#5370619
未解鎖
先求出緯度差DL及橫距P Cn=158 ...
(共 340 字，隱藏中）
前往觀看
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