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50. How does a noncompetitive inhibitor decrease the rate of an enzyme reaction?
(A) by binding to the active site of the enzyme, thus preventing binding of the normal substrate
(B) by binding to an allosteric site, thus changing the shape of the active site of the enzyme
(C) by decreasing the free-energy change of the reaction catalyzed by the enzyme
(D) by acting as a coenzyme for the reaction
(E) by binding to the substrate, thus changing its shape so that it no longer binds to the active site of the enzyme .

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難度： 非常簡單
1F
培源吳 大一下 (2019/08/13)

正確答案是B.

https://baike.baidu.com/item/%E9%9D%9E%E7%AB%9E%E4%BA%89%E6%80%A7%E6%8A%91%E5%88%B6

非竞争性抑制是指有些抑制物往往与酶的非活性部位相结合，形成抑制物一酶的络合物后会进一步再与底物结合；或是酶与底物结合成底物一一酶络合物后，其中有部分再与抑制物结合。虽然底物、抑制物和酶的结合无竞争性，但两者与酶结合所形成的中间络合物不能直接生成产物，导致了酶催化反应速率的降低，这种抑制称为非竞争性抑制。

 allosteric site 異位 https://yamol.tw/item-26.+%E9%85%B5%E7%B4%A0%E7%9A%84%E9%9D%9E%E7%AB%B6%E7%88%AD%E5%9E%8B%E6%8A%91%E5%88%B6%E5%8A%91%28noncompetitive+inhibitor%29..-938966.htm 26. 酵素的...
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2F
李俊毅 高一上 (2020/04/25)

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高醫釋疑答案為B

3F
【站僕】摩檸Morning 國三下 (2020/04/27)
原本答案為D,修改為B


50. How does a noncompetitive inhibitor ..-阿摩線上測驗