26. In the reaction of the Calvin Cycle: 3CO2 + 9ATP + X NADPH → glyceraldehyde-3-phosphate + 9ADP + 9Pi + X NADP+ X = (A)2, (B)4, (C)6, (D)8, (E)10.

26. In the reaction of the Calvin Cycle:

3CO₂ + 9ATP + X NADPH → glyceraldehyde-3-phosphate + 9ADP + 9Pi + X NADP+ X =
(A)2,
(B)4,
(C)6,
(D)8,
(E)10.

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B1 · 2025/09/29

#6810084

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4. A Ramachandran plot shows (A) the amino acid residues which have the greatest degree of rotational freedom, (B) the sterically allowed rotational angles between R groups and α-carbons in a peptide, (C) the sterically allowed rotational angles between Cα and the amide nitrogen (Cα-N) as well as between Cα and the amide carbonyl carbon (Cα-CO), (D) the sterically allowed rotational angles about the amide nitrogen (NH) and CO, (E) the amino acid residues that form α-helix, β-sheet, etc.

26. In the reaction of the Calvin Cycle:

3CO₂ + 9ATP + X NADPH → glyceraldehyde-3-phosphate + 9ADP + 9Pi + X NADP+ X =
(A)2,
(B)4,
(C)6,
(D)8,
(E)10.

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