method 1:
I=12+10=22
22*22*2.5/4=302.5
method 2:
30*1/2+10*1/2*5=55
55*55/4*2.5=302.5
29 如圖所示,試求可變電阻RL可獲得之最大功率為多少W? (A) 200 (B..-阿摩線上測驗