將t=0帶入v(t)= 10 sin(377t+ 30° )=> v(t)=10sin(30)
sin30=0.5 =>v(t)=10*0.5=5V
功率公式P=V*V/R=5*5/10=2.5
37某 10 歐姆電阻兩端所跨電壓為v(t)= 10 sin(377t+ 30°..-阿摩線上測驗