v(t) = 110×sin(337t+60°) = 110×cos(337t-30°) V
i(t) = 11×cos(337t-30°) A
Z = V/I = (110∠-30°) / (11∠-30°) = 10 Ω
該元件之阻抗Z為實數(虛部為0),故該元件為純電阻元件。
37 某元件兩端所跨電壓為 v(t ) = 110 × sin(377t + 6..-阿摩線上測驗