43. E'° of the NAD+/NADH half reaction is -0.32 V. The E'° of the oxaloacetate/malate half reaction is -0.175 V. When the concentrations of NAD+, NADH, oxaloacetate, and malate are all 10⁻5 M, the "spontaneous" reaction is:
(A) malate + NAD⁺ → oxaloacetate + NADH + H⁺.
(B) malate + NADH + H⁺ → oxaloacetate + NAD⁺.
(C) NAD⁺ + NADH + H⁺ → malate + oxaloacetate.
(D) NAD⁺ + oxaloacetate → NADH + H⁺ + malate.
(E) oxaloacetate + NADH + H⁺ → malate + NAD⁺.

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詳解 (共 2 筆)

#6764371
1. 題目解析 這道題目要求我們判斷在特...
(共 1032 字,隱藏中)
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#7289519
E,在人體內的TCA第八步是自發是因為
delta G=delta G0+RTlnK
而體內的OAA濃度非常低,所以delta G變成-的成自發反應
但在非生化環境的情況下,這反應是不自發的
所以這題實際上是問step 8的逆反應式
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