23.艾克曼(Ackerman)遞迴函數之定義如下: A(2,..-阿摩線上測驗
1F 安身立命 國二下 (2016/03/28)
a(2,3)=a(1,a(2,2))
a(2,2)=a(1,a(2,1))
a(2,1)=a(1,a(2,0))
a(2,0)=a(1,1)
a(1,1)=a(0,a(1,0))
a(1,0)=a(0,1)
a(0,1)=2
a(0,2)=3
a(1,3)=a(0,a(1,2))
a(1,2)=a(0,a(1,1))
a(1,1)=a(0,a(1,0))
a(1,0)=a(0,1)
a(0,1)=2
a(0,2)=3
a(0,3)=4
a(0,4)=5
a(1,5)=a(0,a(1,4))
a(1,4)=a(0,a(1,3))
a(1,3)=a(0,a(1,2))
a(1,2)=a(0,a(1,1))
a(1,1)=a(0,a(1,0))
a(1,0)=a(0,1)
a(0,1)=2
a(0,2)=3
a(0,3)=4
a(0,4)=5
a(0,5)=6
a(0,6)=7
a(1,7)=a(0,a(1,6))
a(1,6)=a(0,a(1,5))
a(1,5)=a(0,a(1,4))
a(1,4)=a(0,a(1,3))
a(1,3)=a(0,a(1,2))
a(1,2)=a(0,a(1,1))
a(1,1)=a(0,a(1,0))
a(1,0)=a(0,1)
a(0,1)=2
a(0,2)=3
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2F
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