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23. 艾克曼(Ackerman)遞迴函數之定義如下:   A(2,3)之值為何?
(A) 3 
(B) 6 
(C) 9 
(D) 12


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難度: 困難
1F
安身立命 國二下 (2016/03/28)
a(2,3)=a(1,a(2,2)) a(2,2)=a(1,a(2,1)) a(2,1)=a(1,a(2,0)) a(2,0)=a(1,1) a(1,1)=a(0,a(1,0)) a(1,0)=a(0,1) a(0,1)=2 a(0,2)=3 a(1,3)=a(0,a(1,2)) a(1,2)=a(0,a(1,1)) a(1,1)=a(0,a(1,0)) a(1,0)=a(0,1) a(0,1)=2 a(0,2)=3 a(0,3)=4 a(0,4)=5 a(1,5)=a(0,a(1,4)) a(1,4)=a(0,a(1,3)) a(1,3)=a(0,a(1,2)) a(1,2)=a(0,a(1,1)) a(1,1)=a(0,a(1,0)) a(1,0)=a(0,1) a(0,1)=2 a(0,2)=3 a(0,3)=4 a(0,4)=5 a(0,5)=6 a(0,6)=7 a(1,7)=a(0,a(1,6)) a(1,6)=a(0,a(1,5)) a(1,5)=a(0,a(1,4)) a(1,4)=a(0,a(1,3)) a(1,3)=a(0,a(1,2)) a(1,2)=a(0,a(1,1)) a(1,1)=a(0,a(1,0)) a(1,0)=a(0,1) a(0,1)=2 a(0,2)=3 a(0,3...
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2F
安身立命 國二下 (2016/04/17)
2(N+3)-3=2*6-3=9

23.艾克曼(Ackerman)遞迴函數之定義如下:   A(2,..-阿摩線上測驗