電壓分壓: V*R2/(R1+R2) = 12*8/(8+8) = 6V
*當電容器穩態時,
Vc=VR2
21如圖所示,Vs=12V、R1=8Ω、R2=8Ω、C=30 μF,當電路達穩定..-阿摩線上測驗