Tb/ Tc = 2 / 3 →Tb=Tc*2/3,501*2/3=334 K(Tb)
∆Hv / Tb= 21 cal/mol-K → ∆HV=Tb*21 cal/mol-K,334*21 cal/mol-K=7014 cal/mol=7.014 kcal/mol (∆HV)
11.已知某液體遵循沸點定則: Tb/ Tc = 2 / 3 &nbs..-阿摩線上測驗