周轉輪系,輪4向上迴轉20圈=>N4=+20,輪5向下迴轉10圈=>N5=-10
T2=120,T6=42,T7=21,T3=15
(N4-NA)/(N5-NA)=-[(T2*T7)/T6*T3)]
(20-NA)/(-10-NA)=-[(120*21)/42*15)]
(20-NA)/(-10-NA)=-4
20-NA=40+4NA
5NA=-20
NA=-4
⚠️。注意。向上+ 向下-
864.如圖為一周轉輪系,輪4向上迴轉20圈,輪5向下迴轉10圈,試求輪A的轉數..-阿摩線上測驗