令 f^(-1)(x - 3) = a,f^(-1)(6 - x) = b則 f(a) + f(b) = x - 3 + 6 - x = 3又 f(a) + f(-a) = 3f(-a) = f(b) = 6 - x-a = f^(-1)(6 - x) = ba + b = 0
14.若 f(x)存在反函數 f-1(x)且 f (x) + f (-x) ..-阿摩線上測驗