套ID公式 得ID=5m , VGS=VG-VS , VG接地=0 , VS=5 , RS=VS/ID
ID=IDSS*(1-VGS/VGS(off))^2=20m(A)*(1-(-5)/(-10))^2=5m(A)
RS=-VGS/ID=-(-5)/5mA=1000 ohm
8.如【圖3】當VGS= -5V時,IDSS=20mA及VGS(off)=—10..-阿摩線上測驗