ID=IDss*(1-VGS/VP)^2
1m=4m*(1-VGS/(-4))^2
(-1/2)=VGS/4
VGS=-2V
VG=4V,VS=6V
Rs=6/1m=6k
62.如【圖62】所示,JFET之IDSS = 4 mA,Vp=-4 V,電路偏..-阿摩線上測驗