98、
(A)狹路
(B)狹橋
(C)岔路。

99、 (A)禁止左轉(B)禁止迴車(C)禁止會車。

100、 駕駛人如果在道路上發現圖中的橫向標線時，應 該如何反應？ (A)減速慢行 (B)加速通過 (C) 檢查輪 胎。

1. 下列何者具有最大晶格能？(A)NaF(B)CsI(C)MgO(D)CaS

2. 某個反應當溫度由300K上升至310K時其反應速率恰好變成二倍，試問此反應的活化能為下列何者？ $(R = 8.314 \ \mathrm{J} \cdot \mathrm{mol}^{-1} \cdot \mathrm{K}^{-1})$(A)$6.45 \ \mathrm{kJ} \cdot \mathrm{mol}^{-1}$(B)$23.3 \ \mathrm{kJ} \cdot \mathrm{mol}^{-1}$(C)$53.6 \ \mathrm{kJ} \cdot \mathrm{mol}^{-1}$(D)$178 \ \mathrm{kJ} \cdot \mathrm{mol}^{-1}$

3. $\mathrm{FeS}_{2} + \mathrm{H}^{+} + \mathrm{NO}_{3}^{-} \rightarrow \mathrm{Fe}^{3+} + \mathrm{SO}_{4}^{2-} + \mathrm{NO} + \mathrm{H}_{2}\mathrm{O}$ (未平衡)據平衡後之反應式 $1 \ \mathrm{mole}$ 的 $\mathrm{FeS}_{2}$ 完全溶於硝酸所需之硝酸莫耳數為：(A)1 mole(B)5 mole(C)8 mole(D)14 mole

4. 利用甲：CrCl₃·6NH₃；乙：CrCl₃·5NH₃；丙：CrCl₃·4NH₃；丁：CrCl₃·3NH₃四種化合物，分別配成0.1 M的溶液1升，則下列何者正確？(A)沸點高低順序：丁>丙>乙>甲(B)凝固點高低順序：甲>乙>丙>丁(C)導電度大小順序：甲>乙>丙>丁(D)加入過量 $\mathrm{AgNO_3}$ 時，生成沉澱量大小順序是：丁>丙>乙>甲

5. 氫氧化鎂 $(\mathrm{Mg(OH)_2})$ 飽和水溶液在 $25^{\circ}\mathrm{C}$ 的 $\mathrm{pH}$ 為下列何者？$$\left(K_{\mathrm{sp}} = 6.0 \times 10^{-12} \text{ at } 25^{\circ}\mathrm{C}\right)$$(A)10.56(B)10.36(C)10.26(D)10.05

1. Assuming that you accelerate your car from $10\mathrm{m/s}$ to $25\mathrm{m/s}$ in a distance of $87.5\mathrm{m}$ with a constant acceleration, then the force your body exerts on the car seat (let your mass be $75\mathrm{kg}$) is(A)$550\mathrm{N}$(B)$1100\mathrm{N}$(C)$225\mathrm{N}$(D)$112.5\mathrm{N}$(E)$337.5\mathrm{N}$

2. The initial temperature and volume of an ideal gas are $127^{\circ}\mathrm{C}$ and $23.6\mathrm{L}$ respectively. After an adiabatic expansion, the final temperature and volume of the gas are $27^{\circ}\mathrm{C}$ and $56\mathrm{L}$ respectively. The constant-volume and constant-pressure heat capacities of this ideal gas are(A)$C_V = 1.5R, C_P = 2.5R$(B)$C_V = 2.0R, C_P = 3.0R$(C)$C_V = 2.5R, C_P = 3.5R$(D)$C_V = 3.0R, C_P = 4.0R$(E)$C_V = 3.5R, C_P = 4.5R$

3. The molecular bonding in a diatomic molecule such as the nitrogen $(\mathbf{N}_2)$ molecule can be modeled by the Lennard-Jones potential, which has the form $U(x) = 4U_0\left(\left(\frac{x_0}{x}\right)^{12} - \left(\frac{x_0}{x}\right)^6\right)$, where $x$ is the separation distance between the two nuclei and $x_0$, and $U_0$ are constants. The equilibrium separation $x_0$, which is the value of $x$ for which the two atoms experience zero force from each other, is equal to(A)$2^{-1/6}x_0$(B)$3^{1/6}x_0$(C)$3^{1/3}x_0$(D)$3^{-1/6}x_0$(E)$2^{1/6}x_0$

115年 - 115新北市環保局儲備駕駛考試題目B卷#139538

115年 - 115新北市環保局儲備駕駛考試題目A卷#139534