II. Output the result of the following pseudocode: (20%)

BEGIN
n = 3
FOR i FROM 1 TO n DO
FOR j FROM 1 TO (n - i) DO
PRINT "a", without newline
END FOR
FOR k FROM 1 TO (2 * i - 1) DO
PRINT "*", without newline
END FOR
FOR j FROM 1 TO (2 * (n - i) + 1) DO
PRINT "a", without newline
END FOR
FOR k FROM 1 TO (2 * i - 1) DO
PRINT "*", without newline
END FOR
PRINT newline
END FOR
END