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近期考題
The following C++ code fragment shows the class definition of an array-based implementation of ADT
Binary Tree that stores a list of person names.
【題組】(b) (20 points) Write the BinaryTree : : removeA1 1 Leaf () that removes AL.L, leaf nodes from a binary tree. Note that you also need to implement the BinaryTree: : recurRemo oveLeaf() called by removeAllLeaf() protected function that recursively traverses the tree to delete all the leaf nodes.
(A)承重牆系統因不受梁、柱模矩的限制，因此在建築物完工後，可輕易地改變牆壁位置，增 加室內空間使用彈性
(B)為提升視覺舒適度、氣派感受、或空間趣味性，設計上常見樓板大面積挑空、大廳挑高或 夾層之設計。在此類設計中，落柱會破壞其空間感，因此建築結構可考慮採用承重牆系統
(C)採用承重牆系統時，上下相鄰樓層的牆體應儘量垂直對齊
(D)做為大班制教室（超過百人）使用的建築物，因特殊用途教室與普通教室所需要的空間大 小相差甚多，若採承重牆系統可令空間規劃更具彈性
【題組】47 如果你要改用新的劑量方策（dosage regimen），新的劑量應於何時開始給藥？
(A) 得知血中濃度當天晚上 9 點
(B) 得知血中濃度第二天早上 9 點
(C) 得知血中濃度第二天晚上 9 點
(D) 得知血中濃度第三天早上 9 點
8. (3 points) A randomized linked list sorting algorithm works as follows. We want to build a linked list
in which the keys are in increasing order. That is, every node has a smaller key than its successor in
the list. For ease of discussion we assume that the keys are distinct in integers from 1 to n. The algorithn
randomly picks a key from the rem maining keys, and inserts it into the list. This pro
keys are inserted. The inserted key k will skip those at the beginning of the list that are smaller than
ocess repeats until all
it, and will stop at the first key p that are greater than it. We then insert the key k before p. To ensure
that all keys will stop we assumne that initially the list has only one key, n + 1. After we insert all keys
we will have a sorted linked list from 1 to n + 1.
1. Every inserted key will stop exactly once.
2. The smallest key 1 will not skip any keys.
3. The largest key n will always skip n–1 keys.
4. The expected number of keys that the key i will skip is Ω(i).
of the total number of key comparisons is θ(n2).