104年 - 104 國立嘉義大學_轉學生招生考試試題：普通化學#145291

科目：研究所、轉學考(插大)◆普通化學 | 年份：104年 | 選擇題數：0 | 申論題數：14

試卷資訊

所屬科目：研究所、轉學考(插大)◆普通化學

選擇題 (0)

申論題 (14)

1. Explain Boyle’s law (P and V) by using kinetic molecular theory. (5 points)
2. Explain why the following compound is soluble in water. (10 points)
(A) Sodium chloride, NaCl
(B) Ethanol, C2H5OH.
3. Draw the Lewis structures for ICl3 and tell the molecular geometry, the hybrid orbital used by the
central atom, and molecular polarity. (10 points)
4. For O2, (A) Draw molecular orbital diagram and fill in the valence electrons.
(B) Compare the bond strength of O2 with O2+ based on bond order. (10 points)
5. Explain the forces that bound atoms together in (A) ionic bonding (B) covalent bonding.
(10 points)
6. (A) Calculate the pH of 0.500 M benzoic acid solution. (10 points)
(B) Calculate the pH after 20.0 mL of 1.00 M NaOH was added to 50.0 mL of 0.500 M benzoic
acid solution. (C6H5COOH, Ka = 6.28×10-5)
7. For the following cell: Cu(s)|Cu2+(0.0250M)||Fe3+(0.150M), Fe2+(0.0380M)|Pt(s). E°(Cu2+→Cu)
= 0.34 V, E°(Fe3+→Fe2+) = 0.77 V (10 points)
(A) Write the oxidation and reduction half-reactions.
(B) Calculate the cell potential, Ecell at 25oC, and tell if the cell reaction is spontaneous.
8. Butadiene reacts to form its dimer according to the equation: (10 points)
2C4H6(g) → C8H12(g). The following results were collected:
Time (s) 0 1000 1800 2800 3600
[C4H6] (mol/L) 0.01000 0.00625 0.00476 0.00370 0.00313
(A) Tell if the reaction is first order or second order according to these data.
(B) Calculate the concentration of C4H6 in mol/L at 5000 s.
9. Calculate ∆So for the process that 1 mol (18.02 g) of ice melts at 0oC and increases temperature
to 50oC. ∆Hfus for ice is 6.02 kJ/mol. Specific heat capacity for water is 4.18 J/g⋅K. (10 points)
10. (A) Draw the crystal field diagram for Co(CN)63- and CoF63-. (15 points)
(B) Tell and explain the magnetism of Co(CN)63- and CoF63-.
(C) The wavelengths of absorbed radiation for these compounds are 770 nm and 290 nm (not
respectively). Match the complex ion to the wavelength of radiation and explain.