(更正)2500=(0.6x)²(0.3x)/0.7x
平衡時的mol數比 = N2H4:H2:N2=0.7:0.6:0.3則分壓:PN2H4= P總(0.7/1.6),PH2= P總(0.6/1.6),PN2= P總(0.3/1.6)
K=2500 = (PH22 ‧PN2) / (PN2H4) = [P總(0.7/1.6)]2 ‧ [P總(0.6/1.6)] / [P總(0.3/1.6)] 得P總=204 atm代回 PH2= 204(0.6/1.6) = 76.5 atm
請問解到最後
0.154x^2=2500
x^2=16235
只能用推算的推出x=127嗎?還是有什麼方法呢?
13. 考量肼(hydrazine)的分解反應: N2H4(g)⇌2H2(g) ..-阿摩線上測驗