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115年 - 115-1 臺北市立大安高工教師甄選試題:英文科#138441
> 試題詳解
15.
(A) adversary
(B) actuary
(C) achromatic
(D) almanac
答案:
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統計:
A(25), B(2), C(5), D(5), E(0) #3854940
詳解 (共 1 筆)
YC
B1 · 2026/04/02
#7330352
Daniel Craig repris...
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私人筆記 (共 1 筆)
SHRLY
2026/04/06
私人筆記#7953252
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(A)adversary (n)對手、敵...
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1. Which of the following statements is true? (A) Dynamic electromagnetic forces satisfy Newton's third law (B) Static electromagnetic forces satisfy momentum conservation (C) Given the electric field E = and charge q, the physical meaning of qA is energy. (D) All of the above are true
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4. There is a dielectric-filled parallel-planar metallic waveguide oriented in the way that guided waves propagate along z direction, and the separation d of two parallel is along y axis. Ignoring the fringing effect, the following field component of fundamental mode supported by the waveguide is non-zero: (A) Ez (B) Ex (C) Hy (D) Hx
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5. In the complex notation (also called the phasor notation), we can express a monochromatic plane wave as E = E₀ei(k·r-ωt). How do we calculate the time-averaged Poynting vector in this notation? (A) E × H (B) Re[E × H] (C) Re[E × H*] (D) None of the above
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6. Consider a plane wave traveling in a lossy material. The electric field is given by E = E₀ei(kz-ωt), where k equals 1 + 0.1i (μm⁻¹). The intensity of the plane wave can be expressed as I = I₀e-αz, where α is the absorption coefficient. Please calculate α. (A) 2 (μm⁻¹) (B) 0.2 (μm⁻¹) (C) 0.1 (μm⁻¹) (D) None of the above
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8. The finite sheet 0 ≤ x ≤ 1 and 0 ≤ y ≤ 1 on the z = 0 plane has a surface charge density ρs = xy(x² + y² + 25)3/2 nC/m². Evaluate the electric field at (0, 0, 5).(A) -3 x̂ - 3 ŷ + 22.5 ẑ V/m (B) -3 x̂ - 3 ŷ + 11.25 ẑ V/m (C) -1.5 x̂ - 1.5 ŷ + 22.5 ẑ V/m (D) -1.5 x̂ - 1.5 ŷ + 11.25 ẑ V/m
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9. In the following figure, two conducting cones of infinite extent with θ₁ and θ₂ are separated by an infinitesimal gap at R = 0. If 0 < θ₁ < θ₂ < , V(θ₁) = 0, and V(θ₂) = 10 V, evaluate the potential distribution V(θ) between the cones. (A) 10V (B) 10 V (C) 10 [ln(tan θ cot θ₁)] / [ln(tan θ₂ cot θ₁)] V (D) 10 [ln(tan 2θ cot 2θ₁)] / [ln(tan 2θ₂ cot 2θ₁)] V
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