25 Calculate activation energy, Ea (kcal/mol) for a reaction whose rate at room temperature (298 K) is doubled by a 20°C increase in T. (ln 2 =0.693, R = 8.314 J mol^-1K^-1)
(A)12.3KJ/mol
(B) 16.3KJ/mol
(C) 20.5KJ/mol
(D) 14.2KJ/mol
(E) 27.3KJ/mol

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