4. A 0.20-kg particle moves along the x axis under the influence of a conservative force field. The potential energy is given by
U(x) = (8.0J/m²)x² + (2.0J/m²)x⁴,
where x is in coordinate of the particle. If the particle has a speed of 5.0 m/s when it is at the origin, what is its speed when it is at x =1.0 m?
(A) 0
(B) 2.5 m/s
(C) 7.9 m/s
(D) 11 m/s
(E) The particle can't reach the position x = 1.0 m.

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詳解 (共 2 筆)

#7415040
所以這題用能量守恆來想(因為conservative force field)
初始E=動能+位能
6a375c75d9580.jpg
x=1的地方
U(1)=10J
而大於總能量2.5J
所以無法到達
ㅤㅤ
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#6802699
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