50. The reaction between SbF₄ and two equivalents of HF leads to the formation of
(A) SbF₃ + H₂ + 2F₂
(B) [SbF₆]⁻[H₂F]⁺
(C) HSbF₂ + 3F₂
(D) H₂SbF₃⁺ 2F₂
(E) [SbF₄]⁺[HF₂]⁻

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