7. 求無窮等比級數 1+(-0.5)+(-0.5)2+(-0.5)3+....+(-0.5)n+....的和是多少?
(A) 1/3
(B)2/3
(C) 1
(D) 2
(E) 0
答案:登入後查看
統計: A(14), B(172), C(40), D(7), E(25) #713283
統計: A(14), B(172), C(40), D(7), E(25) #713283
詳解 (共 3 筆)
#984268
1+(-0.5)+(-0.5)2+(-0.5)3+....+(-0.5)n+....
=[1+(-0.5)2+(-0.5)4+......+(-0.5)n+.......]+[(-0.5)+(-0.5)3+......+(-0.5)n+......]
=[1/1-(-0.5)2]+[(-0.5)/1-(-0.5)2]
=2/3
0
0