8．You found an interesting looking piece of metal. You want to find out what kind of metal that is and so you decide to replace the cathode in your photoelectric effect apparatus with that metal piece. You stillhave the laser diode from the blue-ray player (405 nm Metal surface wavelength). In this setup you find a stopping potential of 0.16 eV. What kind of metal is it? (A)Sodium (Φ≈2.3 eV) (B)Calcium (Φ≈2.9 eV) (C)Silver (Φ≈4.7 eV) (D)Lead (Φ≈4.1 eV) (E)Some other material

1. For a particle with an energy of E tunneling through a finite barrier height of U and width of & solve the Schrodinger wave equation to calculate the tunneling probability and select the correct answer corresponding to various E, U, and 8 for different particles. (A) For a neutron with E = 50 meV incident on a barrier of U = 250 meV and 8 = 0.16 nm, the tunneling probability is 4.45×10-11 = 0.0445 ppb (B) For a neutron with E = 50 meV incident on a barrier of U = 250 meV and 8 = 0.1 nm, the tunneling probability is 5.86×10-10 = 0.586 ppb (C) For an electron with E = 1.0 eV incident on a barrier with U = 5.0 eV and 8 = 0.5 nm, the tunneling probability is 7.1×10-7 = 0.71 ppm (D) For an electron with E = 1.0 eV incident on a barrier with U = 5.0 eV and 8 = 1.0 nm, the tunneling probability is 2.52×10-9 =2.52 ppb (E) For an electron with E = 1.0 eV incident on a barrier with U = 5.0 eV and & = 1.25 nm, the tunneling probability is 1.5×10-10 = 0.15 ppb

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