13.Why do acetal-forming reactions that use ethylene glycol (HOCH2CH2OH) have more favorable equilibrium constants than those using methanol?
(A) Ethylene glycol reacts more rapidly.
(B) They are more favorable on entropy grounds.
(C) They are more favorable on enthalpy grounds.
(D) Ethylene glycol is acidic and catalyzes the reaction.
(E) The ethylene acetal can serve as a protecting group.

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統計: A(2), B(1), C(0), D(0), E(0) #3437010

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1. 題目解析 本題探討以乙二醇(HO...
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縮醛形成反應(Acetal forma...
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