2. Perform the following calculation to the correct number of significant figures. 56.55×0.920÷34.2585= (A) 1.519 (B) 1.5186 (C) 1.52 (D) 1.5185

2. Perform the following calculation to the correct number of significant figures. 56.55×0.920÷34.2585=
(A) 1.519
(B) 1.5186
(C) 1.52
(D) 1.5185

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詳解 (共 1 筆)

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B1 · 2026/10/03

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這題在考什麼觀念有效數字（Signi...

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12. Lead(II) nitrate reacts with sodium chloride in aqueous solution to form a precipitate. What is the net ionic equation for this reaction?(A) \( \text{Pb}^{2+}(aq) + 2\text{NO}_3^-(aq) \rightarrow \text{Pb}(\text{NO}_3)_2(s) \) (B) \( \text{Na}^+(aq) + \text{Cl}^-(aq) \rightarrow \text{NaCl}(s) \) (C) \( \text{Pb}^{2+}(aq) + 2\text{Cl}^-(aq) \rightarrow \text{PbCl}_2(s) \) (D) \( \text{Na}^+(aq) + \text{NO}_3^-(aq) \rightarrow \text{NaNO}_3(s) \)

2. Perform the following calculation to the correct number of significant figures. 56.55×0.920÷34.2585=
(A) 1.519
(B) 1.5186
(C) 1.52
(D) 1.5185

詳解 (共 1 筆)

相關試題

相關試卷

2. Perform the following calculation to the correct number of significant figures. 56.55×0.920÷34.2585=(A) 1.519(B) 1.5186(C) 1.52(D) 1.5185

詳解 (共 1 筆)

相關試題

相關試卷

2. Perform the following calculation to the correct number of significant figures. 56.55×0.920÷34.2585=
(A) 1.519
(B) 1.5186
(C) 1.52
(D) 1.5185