24.如【圖 24】所示交流網路,其戴維寧等效分別為何?
(A) ETH = 6+j12;ZTH = 6+j6
(B) ETH = 6+j12;ZTH = 6-j6
(C) ETH = 6+j6;ZTH = 6-j6
(D) ETH = 6+j6;ZTH = 6+j12
答案:登入後查看
統計: A(121), B(32), C(18), D(28), E(0) #2403120
統計: A(121), B(32), C(18), D(28), E(0) #2403120
詳解 (共 2 筆)
#5273512
算ZTH 。電壓源短路 30並j15 串-j6
ZTH =j30*15*(30-j15)/(1125) - j6 = j6*(2-j1)-j6 = 6+j12-j6 = 6+j6
ETH 。 算分壓 j15
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