3. The vitamin C content in a bottle of juice is determined by a titration method with potassium iodate based on the following equations. The total volume of juice is 500 mL and a portion of 100 mL is titrated with 0.01 M KIO3(aq) in the acidic condition. The volume of titrant required to reach the end point is 20.00 mL. Calculate the mass of vitamin C in the bottle of juice. (The molecular weight of vitamin C is 176 g/mol.)

\( \mathrm{KIO_3} + 5\mathrm{KI} + 6\mathrm{H^+} \longrightarrow 3\mathrm{I_2} + 6\mathrm{K^+} + 3\mathrm{H_2O} \)

\( \mathrm{C_6H_8O_6} + \mathrm{I_2} \longrightarrow \mathrm{C_6H_6O_6} + 2\mathrm{I^-} + 2\mathrm{H^+} \)

(A) 0.1056 g
(B) 0.528 g
(C) 0.176 g
(D) 0.0352 g
(E) None of the above