8. From a population that is normally distributed with an unknown standard deviation, a sample of 25 elements is selected. For the interval estimation of μ, the proper distribution to use is the
(A) standard normal distribution
(B) \(z\) distribution
(C) \(t\) distribution with 26 degrees of freedom
(D) \(t\) distribution with 24 degrees of freedom

9. It is known that the population variance equals 484. With a 0.95 probability, the sample size that needs to be taken to estimate the population mean if the desired margin of error is 5 or less is (A) 25 (B) 74 (C) 189 (D) 75

10. The manager of an automobile dealership is considering a new bonus plan in order to increase sales. Currently, the mean sales rate per salesperson is five automobiles per month. The correct set of hypotheses for testing the effect of the bonus plan is (A) \(\mathrm{H}_0: \mu < 5\) \(\mathrm{H}_{\mathrm{a}}: \mu \leq 5\) (B) \(\mathrm{H}_0: \mu \leq 5\) \(\mathrm{H}_{\mathrm{a}}: \mu > 5\) (C) \(\mathrm{H}_0: \mu > 5\) \(\mathrm{H}_{\mathrm{a}}: \mu \leq 5\) (D) \(\mathrm{H}_0: \mu \geq 5\) \(\mathrm{H}_{\mathrm{a}}: \mu < 5\)

11. When the p-value is used for hypothesis testing, the null hypothesis is rejected if (A) \(p\) -value \(\leq \alpha\) (B) \(\alpha \leq p\) -value (C) \(p\) -value \(\geq \alpha\) (D) \(p\) -value \(= \alpha\)

12. If we are interested in testing whether the mean of population 1 is smaller than the mean of population 2, the (A) null hypothesis should state \(\mu_{1} - \mu_{2} < 0\) (B) null hypothesis should state \(\mu_{1} - \mu_{2} > 0\) (C) alternative hypothesis should state \(\mu_{1} - \mu_{2}\geq 0\) (D) None of the other answers is correct.

13. Below you are given a partial computer output based on a sample of 16 observations. | | Coefficient | Standard Error | | --- | --- | --- | | Constant | 12.924 | 4.425 | | X₁ | -3.682 | 2.630 | | X₂ | 45.216 | 12.560 | The estimated regression equation is (A) \(y = \beta_0 + \beta_1x_1 + \beta_2x_2 + \varepsilon\) (B) \(E(y) = \beta_0 + \beta_1x_1 + \beta_2x_2 + \varepsilon\) (C) \(\hat{y} = 12.924 - 3.682x_{1} + 45.216x_{2}\) (D) \(\hat{y} = 4.425 - 2.63x_{1} + 12.56x_{2}\)

14. The table below gives beverage preferences for random samples of teens and adults. | Beverage | Teens | Adults | Total | | --- | --- | --- | --- | | Coffee | 50 | 200 | 250 | | Tea | 100 | 150 | 250 | | Soft Drink | 200 | 200 | 400 | | Other | 50 | 50 | 100 | | | 400 | 600 | 1,000 | We are asked to test for independence between age (i.e., adult and teen) and drink preferences. The result of the test is that the (A) hypothesis of independence can be rejected (B) hypothesis of independence cannot be rejected (C) test is inconclusive (D) None of these alternatives is correct.

115年 - 115 國立臺北大學_日間學士班轉學生招生考試試題_統計學系日間學士班2、3年級 金融與合作經營學日間學士班3年級：統計學#147585

115年 - 115 國立臺北大學_碩士班一般入學考試試題_國際企業研究所：統計學#147120

115年 - 115 國立臺北大學_碩士班一般入學考試試題_統計學系：統計學#147104

115年 - 115 國立臺北大學_碩士班一般入學考試試題_自然資源與環境管理研究所：統計學#146969

115年 - 110 國立臺北大學_碩士班一般入學考試試題_企業管理學系甲組：統計學#146951

115年 - 115 國立臺北大學_碩士班一般入學考試試題_金融與合作經營學系：統計學#146920

115年 - [無官方正解]115 國立臺北大學_碩士班一般入學考試試題_經濟學系：統計學#146534

115年 - [無官方正解]115 國立嘉義大學_碩士班招生考試試題_財務金融學系：統計學#143862

115年 - 115 中央警察大學_碩士班入學考試試題：統計學#139759

114年 - 114 國立臺北大學_日間學士班轉學生招生考試試題_統計學系日間學士班2、3年級 金融與合作經營學日間學士班3年級：統計學#147628