3. 已知6OH+Br→ BrO3+3H2O+6e E0 =-0.61V;2OH+Br→ BrO+H2O+ 2e E0 =-0.76V;計算 BrO+4OH→ BrO3+2H2O+4e之E0 為何?
(A)0.15V
(B)-0.535V
(C)-0.15V
(D)0.535V

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統計: A(3), B(10), C(4), D(0), E(0) #2342452

詳解 (共 1 筆)

#4103277
4×E'=6×-0.61+2×0.76E...
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