3. 已知6OH—+Br—→ BrO3 —+3H2O+6e— E0 =-0.61V;2OH—+Br—→ BrO—+H2O+ 2e— E0 =-0.76V;計算 BrO—+4OH—→ BrO3 —+2H2O+4e—之E0 為何? (A)0.15V(B)-0.535V(C)-0.15V(D)0.535V