試卷名稱:92年 - [無官方正解]92 高雄醫學大學學士後醫學系_招生考試試題:化學#136240
年份:92年
科目:學士後西醫-化學
68. Arrange following 0.10 M solutions from lowest to highest pH: NaF, NaC2H3O2, C5H5NHCl, KOH, HCN. (Ka for HCN is 6.2 × 10-10; Ka for HF is 7.2 × 10-4; Ka for HC2H3O2 is 1.8 × 10-5; Kb for C5H5N is 1.7 × 10-9)
(A) HCN, C5H5NHCl, NaF, NaC2H3O2, KOH
(B) C5H5NHCl, HCN, NaF, NaC2H3O2, KOH
(C) NaF, NaC2H3O2, HCN, C5H5NHCl, KOH
(D) KOH, NaC2H3O2, NaF, HCN, C5H5NHCl
(E) None of these