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111年 - 111 國立中山大學_學士後醫學系招生考試:物理及化學#113520
> 試題詳解
80. Which reagent would convert 1,3-octadiene into 3-octen-2-ol?
(A) KMnO
4
/
-
OH
(B)OsO
4
(C)mCPBA, then H
3
O
+
(D) Cl
2
/H
2
O
(E) H
3
O
+
答案:
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統計:
A(4), B(0), C(7), D(0), E(8) #3081320
詳解 (共 2 筆)
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B1 · 2023/12/07
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