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申論題資訊

試卷:104年 - 台南一中104學年度教甄 生物科#20362
科目:教甄◆生物專業
年份:104年
排序:0

申論題內容

26. In the peppered month (B ist on be ml aria), black individuals may be either homozygous (A1A1) or heterozygous (A1A2), whereas pale gray months are homozygous (A2A2). Suppose that in a sample of 250 months from one locality, 108 are black and 142 are gray, (a) Which allele is dominant? (b) Assuming that the locus is in Hardy-Weinberg equilibrium, what are the allele irequencies? (c) Under this assumption, please describe Ho (Observed heterozygosity), He (Expect heterozygosity) and Fis. (6 分)

詳解 (共 1 筆)

詳解 提供者:Iry Kuo

(a)黑蛾基因是顯性。 (b)白蛾 a^2=142/250 a=0.75 A=1-0.75 = 0.25 ( A^2 + 2Aa + a^2 = 1 ) (c) Ho = 2Aa = 2 * 0.75 * 0.25 = 0.375 He = 0.375 Fis =