已知n (A∩B)= n (A∩C)= n (B∩C)=6, n
(A)= n
(B)= n
(C)=11, n (A∩B∩C)=3,則n (A∪B∪C)=
(A)16
(B)18
(C)20
(D)22
(A)= n
(B)= n
(C)=11,
(A)16
(B)18
(C)20
(D)22
答案:登入後查看
統計: A(34), B(235), C(126), D(34), E(2) #99010
統計: A(34), B(235), C(126), D(34), E(2) #99010
詳解 (共 9 筆)
#344420
原題目請更改為
n (A∩B)= n (A∩C)= n (B∩C)=6, n (A)= n (B)= n (C)=11, n (A∩B∩C)=3,則n (A∪B∪C)=
11*3-6*3+3=18
n (A∩B)= n (A∩C)= n (B∩C)=6, n (A)= n (B)= n (C)=11, n (A∩B∩C)=3,則n (A∪B∪C)=
11*3-6*3+3=18
7
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#416788
畫圖ㄅ,圖畫好答案就出來了,前後不到10秒~
U是連集,n是交集~
1
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#206438
第一次看過這種符號...
1
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#168061
Ç 和 È 應該是聯集的意思
1
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#320145
請求高手解題
1
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#107750
看不懂!!
1
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#691224
看到解答是正常顯示... 但是正在寫題目的時候看到的還是一堆亂七八糟的abc啦~~ @@
0
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#675690
看不懂題目一堆ABC
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