18.兩個電阻R1與R2並聯,計算R2支路電流的分流公式是(I為總電流,U為總電壓):
(A)I2= R1I/(R1+R2)
(B)I 2= R2I/(R1+R2)
(C)I2 = R1U/(R1+R2)
(D)I2= R2U/(R1+R2)
(A)I2= R1I/(R1+R2)
(B)I 2= R2I/(R1+R2)
(C)I2 = R1U/(R1+R2)
(D)I2= R2U/(R1+R2)
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統計: A(290), B(47), C(66), D(25), E(0) #930062
統計: A(290), B(47), C(66), D(25), E(0) #930062
詳解 (共 1 筆)
#1272416
V=IR 電阻並聯R1xR2/R1+R2
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