4. The potential energy of a 0.20-kg particle moving along the x axis under a conservative force field is: U(x) =(8.0J/m²)x² - (2.0J/m²)x⁴ When the particle is at x = 1.0 m, its acceleration is:
(A) 0 î
(B) -8 m/s² î
(C) 8 m/s² î
(D) -40 m/s² î
(E) 40 m/s² î.

答案:登入後查看
統計: 尚無統計資料

詳解 (共 1 筆)

#6802753
1. 題目解析 題目要求計算在某一點(x...
(共 1168 字,隱藏中)
前往觀看
0
0