7 若 P
(A) = 0.3,P
(B) = 0.4,且 A 的餘集合 Ac 與 B 的餘集合 B c 互為獨立事件,則 P(Ac ∩B c ) =?
(A)0.42
(B)0.12
(C)0.75
(D)0.7
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統計: A(126), B(13), C(0), D(9), E(0) #1204338
統計: A(126), B(13), C(0), D(9), E(0) #1204338
詳解 (共 2 筆)
#1406699
P(A) = 0.3
P(Ac ) = 1-P(A) = 1-0.3 = 0.7
P(B) = 0.4
P(B c ) = 1-P(B) = 1-0.4 = 0.6
因P(Ac )與P(B c )互為獨立事件
則 P(Ac ∩B c ) = P(Ac )*P(B c ) = 0.7*0.6 = 0.42
4
0
#3740878
P(Ac ∩B c )=1-P(AUB)
P(AUB)=P(A)+P(B)-P(A∩B)=0.3+0.4-0.3*0.4=0.58
因此P(Ac ∩B c )=1-0.58=0.42
1
0