26 有五個電阻器,電阻值各為RΩ,今接成如圖所示之電路,已知VA=2 伏特,則電源E為多少伏特? 
(A)3
(B) 5
(C) 6
(D)8
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統計: A(14), B(245), C(37), D(15), E(0) #1210818
統計: A(14), B(245), C(37), D(15), E(0) #1210818
詳解 (共 2 筆)
#3873674
VA=2V
VA=IT*(R//R//R)
2=IT*(R/3) =>IT=6/R
RT=(R//R)+(R//R//R)=R/2+R/3=(5/6)R
E=IT*RT=6/R*(5/6)R=5V
3
0