14.若 f(x)存在反函數 f-1(x)且 f (x) + f (-x) = 3 ，則 f-1(x-3)+f-1(6-x)=?
(A) - 2
(B) -1
(C) 0
(D) 1

答案：登入後查看
統計： A(16), B(35), C(55), D(17), E(0) #871241

詳解 (共 2 筆)

#2981571
若存在y不等於-x且能滿足f(x)+f(...
(共 168 字，隱藏中）
前往觀看
10
0
#1602810

令 f^(-1)(x - 3) = a，f^(-1)(6 - x) = b
則 f(a) + f(b) = x - 3 + 6 - x = 3
又 f(a) + f(-a) = 3
f(-a) = f(b) = 6 - x
-a = f^(-1)(6 - x) = b
a + b = 0

6
0